Adam has 490 stickers.
After
15 of the green stickers and
40 red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers than red stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Red stickers |
Total |
Before |
5 u |
4 u + 40 |
490 |
Change |
- 1 u |
- 40 |
|
After |
4 u |
4 u |
|
(a)
Fraction of the green stickers left
= 1 -
15 =
45 Total number of stickers at first
= 5 u + 4 u + 40
= 9 u + 40
9 u + 40 = 490
9 u = 490 - 40
9 u = 450
1 u = 450 ÷ 9 = 50
Number of green stickers in the end
= 4 u
= 4 x 50
= 200
(b)
Number of more green stickers than red stickers at first
= 5 u - (4 u + 40)
= 5 u - 4 u - 40
= 1 u - 40
= 1 x 50 - 40
= 50 - 40
= 10
(c)
Number of green stickers given away
= 1 u
= 50
Answer(s): (a) 200; (b) 10; (c) 50