Adam has 460 stickers.
After
16 of the blue stickers and
20 red stickers are given away,
there is an equal number of blue and red stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers than red stickers are there at first?
- How many blue stickers are given away?
|
Blue stickers |
Red stickers |
Total |
Before |
6 u |
5 u + 20 |
460 |
Change |
- 1 u |
- 20 |
|
After |
5 u |
5 u |
|
(a)
Fraction of the blue stickers left
= 1 -
16 =
56 Total number of stickers at first
= 6 u + 5 u + 20
= 11 u + 20
11 u + 20 = 460
11 u = 460 - 20
11 u = 440
1 u = 440 ÷ 11 = 40
Number of blue stickers in the end
= 5 u
= 5 x 40
= 200
(b)
Number of more blue stickers than red stickers at first
= 6 u - (5 u + 20)
= 6 u - 5 u - 20
= 1 u - 20
= 1 x 40 - 20
= 40 - 20
= 20
(c)
Number of blue stickers given away
= 1 u
= 40
Answer(s): (a) 200; (b) 20; (c) 40