Adam has 380 stickers.
After
13 of the green stickers and
40 red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers than red stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Red stickers |
Total |
Before |
3 u |
2 u + 40 |
380 |
Change |
- 1 u |
- 40 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the green stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 40
= 5 u + 40
5 u + 40 = 380
5 u = 380 - 40
5 u = 340
1 u = 340 ÷ 5 = 68
Number of green stickers in the end
= 2 u
= 2 x 68
= 136
(b)
Number of more green stickers than red stickers at first
= 3 u - (2 u + 40)
= 3 u - 2 u - 40
= 1 u - 40
= 1 x 68 - 40
= 68 - 40
= 28
(c)
Number of green stickers given away
= 1 u
= 68
Answer(s): (a) 136; (b) 28; (c) 68