Adam has 290 stickers.
After
13 of the red stickers and
30 green stickers are given away,
there is an equal number of red and green stickers left.
- How many red stickers are there in the end?
- How many more red stickers than green stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Green stickers |
Total |
Before |
3 u |
2 u + 30 |
290 |
Change |
- 1 u |
- 30 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the red stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 30
= 5 u + 30
5 u + 30 = 290
5 u = 290 - 30
5 u = 260
1 u = 260 ÷ 5 = 52
Number of red stickers in the end
= 2 u
= 2 x 52
= 104
(b)
Number of more red stickers than green stickers at first
= 3 u - (2 u + 30)
= 3 u - 2 u - 30
= 1 u - 30
= 1 x 52 - 30
= 52 - 30
= 22
(c)
Number of red stickers given away
= 1 u
= 52
Answer(s): (a) 104; (b) 22; (c) 52