Adam has 410 stickers.
After
13 of the red stickers and
50 green stickers are given away,
there is an equal number of red and green stickers left.
- How many red stickers are there in the end?
- How many more red stickers than green stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Green stickers |
Total |
Before |
3 u |
2 u + 50 |
410 |
Change |
- 1 u |
- 50 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the red stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 50
= 5 u + 50
5 u + 50 = 410
5 u = 410 - 50
5 u = 360
1 u = 360 ÷ 5 = 72
Number of red stickers in the end
= 2 u
= 2 x 72
= 144
(b)
Number of more red stickers than green stickers at first
= 3 u - (2 u + 50)
= 3 u - 2 u - 50
= 1 u - 50
= 1 x 72 - 50
= 72 - 50
= 22
(c)
Number of red stickers given away
= 1 u
= 72
Answer(s): (a) 144; (b) 22; (c) 72