Adam has 440 stickers.
After
13 of the blue stickers and
70 green stickers are given away,
there is an equal number of blue and green stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers than green stickers are there at first?
- How many blue stickers are given away?
|
Blue stickers |
Green stickers |
Total |
Before |
3 u |
2 u + 70 |
440 |
Change |
- 1 u |
- 70 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the blue stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 70
= 5 u + 70
5 u + 70 = 440
5 u = 440 - 70
5 u = 370
1 u = 370 ÷ 5 = 74
Number of blue stickers in the end
= 2 u
= 2 x 74
= 148
(b)
Number of more blue stickers than green stickers at first
= 3 u - (2 u + 70)
= 3 u - 2 u - 70
= 1 u - 70
= 1 x 74 - 70
= 74 - 70
= 4
(c)
Number of blue stickers given away
= 1 u
= 74
Answer(s): (a) 148; (b) 4; (c) 74