Adam has 470 stickers.
After
14 of the red stickers and
50 blue stickers are given away,
there is an equal number of red and blue stickers left.
- How many red stickers are there in the end?
- How many more red stickers than blue stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Blue stickers |
Total |
Before |
4 u |
3 u + 50 |
470 |
Change |
- 1 u |
- 50 |
|
After |
3 u |
3 u |
|
(a)
Fraction of the red stickers left
= 1 -
14 =
34 Total number of stickers at first
= 4 u + 3 u + 50
= 7 u + 50
7 u + 50 = 470
7 u = 470 - 50
7 u = 420
1 u = 420 ÷ 7 = 60
Number of red stickers in the end
= 3 u
= 3 x 60
= 180
(b)
Number of more red stickers than blue stickers at first
= 4 u - (3 u + 50)
= 4 u - 3 u - 50
= 1 u - 50
= 1 x 60 - 50
= 60 - 50
= 10
(c)
Number of red stickers given away
= 1 u
= 60
Answer(s): (a) 180; (b) 10; (c) 60