Adam has 310 stickers.
After
13 of the blue stickers and
50 red stickers are given away,
there is an equal number of blue and red stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers than red stickers are there at first?
- How many blue stickers are given away?
|
Blue stickers |
Red stickers |
Total |
Before |
3 u |
2 u + 50 |
310 |
Change |
- 1 u |
- 50 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the blue stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 50
= 5 u + 50
5 u + 50 = 310
5 u = 310 - 50
5 u = 260
1 u = 260 ÷ 5 = 52
Number of blue stickers in the end
= 2 u
= 2 x 52
= 104
(b)
Number of more blue stickers than red stickers at first
= 3 u - (2 u + 50)
= 3 u - 2 u - 50
= 1 u - 50
= 1 x 52 - 50
= 52 - 50
= 2
(c)
Number of blue stickers given away
= 1 u
= 52
Answer(s): (a) 104; (b) 2; (c) 52