Adam has 460 stickers.
After
13 of the blue stickers and
60 red stickers are given away,
there is an equal number of blue and red stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers than red stickers are there at first?
- How many blue stickers are given away?
|
Blue stickers |
Red stickers |
Total |
Before |
3 u |
2 u + 60 |
460 |
Change |
- 1 u |
- 60 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the blue stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 60
= 5 u + 60
5 u + 60 = 460
5 u = 460 - 60
5 u = 400
1 u = 400 ÷ 5 = 80
Number of blue stickers in the end
= 2 u
= 2 x 80
= 160
(b)
Number of more blue stickers than red stickers at first
= 3 u - (2 u + 60)
= 3 u - 2 u - 60
= 1 u - 60
= 1 x 80 - 60
= 80 - 60
= 20
(c)
Number of blue stickers given away
= 1 u
= 80
Answer(s): (a) 160; (b) 20; (c) 80