Adam has 230 stickers.
After
14 of the green stickers and
20 red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers than red stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Red stickers |
Total |
Before |
4 u |
3 u + 20 |
230 |
Change |
- 1 u |
- 20 |
|
After |
3 u |
3 u |
|
(a)
Fraction of the green stickers left
= 1 -
14 =
34 Total number of stickers at first
= 4 u + 3 u + 20
= 7 u + 20
7 u + 20 = 230
7 u = 230 - 20
7 u = 210
1 u = 210 ÷ 7 = 30
Number of green stickers in the end
= 3 u
= 3 x 30
= 90
(b)
Number of more green stickers than red stickers at first
= 4 u - (3 u + 20)
= 4 u - 3 u - 20
= 1 u - 20
= 1 x 30 - 20
= 30 - 20
= 10
(c)
Number of green stickers given away
= 1 u
= 30
Answer(s): (a) 90; (b) 10; (c) 30