Adam has 220 stickers.
After
13 of the green stickers and
30 red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers than red stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Red stickers |
Total |
Before |
3 u |
2 u + 30 |
220 |
Change |
- 1 u |
- 30 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the green stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 30
= 5 u + 30
5 u + 30 = 220
5 u = 220 - 30
5 u = 190
1 u = 190 ÷ 5 = 38
Number of green stickers in the end
= 2 u
= 2 x 38
= 76
(b)
Number of more green stickers than red stickers at first
= 3 u - (2 u + 30)
= 3 u - 2 u - 30
= 1 u - 30
= 1 x 38 - 30
= 38 - 30
= 8
(c)
Number of green stickers given away
= 1 u
= 38
Answer(s): (a) 76; (b) 8; (c) 38