Adam has 440 stickers.
After
18 of the green stickers and
20 blue stickers are given away,
there is an equal number of green and blue stickers left.
- How many green stickers are there in the end?
- How many more green stickers than blue stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Blue stickers |
Total |
Before |
8 u |
7 u + 20 |
440 |
Change |
- 1 u |
- 20 |
|
After |
7 u |
7 u |
|
(a)
Fraction of the green stickers left
= 1 -
18 =
78 Total number of stickers at first
= 8 u + 7 u + 20
= 15 u + 20
15 u + 20 = 440
15 u = 440 - 20
15 u = 420
1 u = 420 ÷ 15 = 28
Number of green stickers in the end
= 7 u
= 7 x 28
= 196
(b)
Number of more green stickers than blue stickers at first
= 8 u - (7 u + 20)
= 8 u - 7 u - 20
= 1 u - 20
= 1 x 28 - 20
= 28 - 20
= 8
(c)
Number of green stickers given away
= 1 u
= 28
Answer(s): (a) 196; (b) 8; (c) 28