Adam has 290 stickers.
After
13 of the red stickers and
40 green stickers are given away,
there is an equal number of red and green stickers left.
- How many red stickers are there in the end?
- How many more red stickers than green stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Green stickers |
Total |
Before |
3 u |
2 u + 40 |
290 |
Change |
- 1 u |
- 40 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the red stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 40
= 5 u + 40
5 u + 40 = 290
5 u = 290 - 40
5 u = 250
1 u = 250 ÷ 5 = 50
Number of red stickers in the end
= 2 u
= 2 x 50
= 100
(b)
Number of more red stickers than green stickers at first
= 3 u - (2 u + 40)
= 3 u - 2 u - 40
= 1 u - 40
= 1 x 50 - 40
= 50 - 40
= 10
(c)
Number of red stickers given away
= 1 u
= 50
Answer(s): (a) 100; (b) 10; (c) 50