Adam has 470 stickers.
After
13 of the red stickers and
60 blue stickers are given away,
there is an equal number of red and blue stickers left.
- How many red stickers are there in the end?
- How many more red stickers than blue stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Blue stickers |
Total |
Before |
3 u |
2 u + 60 |
470 |
Change |
- 1 u |
- 60 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the red stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 60
= 5 u + 60
5 u + 60 = 470
5 u = 470 - 60
5 u = 410
1 u = 410 ÷ 5 = 82
Number of red stickers in the end
= 2 u
= 2 x 82
= 164
(b)
Number of more red stickers than blue stickers at first
= 3 u - (2 u + 60)
= 3 u - 2 u - 60
= 1 u - 60
= 1 x 82 - 60
= 82 - 60
= 22
(c)
Number of red stickers given away
= 1 u
= 82
Answer(s): (a) 164; (b) 22; (c) 82