Adam has 440 stickers.
After
14 of the green stickers and
20 blue stickers are given away,
there is an equal number of green and blue stickers left.
- How many green stickers are there in the end?
- How many more green stickers than blue stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Blue stickers |
Total |
Before |
4 u |
3 u + 20 |
440 |
Change |
- 1 u |
- 20 |
|
After |
3 u |
3 u |
|
(a)
Fraction of the green stickers left
= 1 -
14 =
34 Total number of stickers at first
= 4 u + 3 u + 20
= 7 u + 20
7 u + 20 = 440
7 u = 440 - 20
7 u = 420
1 u = 420 ÷ 7 = 60
Number of green stickers in the end
= 3 u
= 3 x 60
= 180
(b)
Number of more green stickers than blue stickers at first
= 4 u - (3 u + 20)
= 4 u - 3 u - 20
= 1 u - 20
= 1 x 60 - 20
= 60 - 20
= 40
(c)
Number of green stickers given away
= 1 u
= 60
Answer(s): (a) 180; (b) 40; (c) 60