Adam has 470 stickers.
After
13 of the green stickers and
70 blue stickers are given away,
there is an equal number of green and blue stickers left.
- How many green stickers are there in the end?
- How many more green stickers than blue stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Blue stickers |
Total |
Before |
3 u |
2 u + 70 |
470 |
Change |
- 1 u |
- 70 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the green stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 70
= 5 u + 70
5 u + 70 = 470
5 u = 470 - 70
5 u = 400
1 u = 400 ÷ 5 = 80
Number of green stickers in the end
= 2 u
= 2 x 80
= 160
(b)
Number of more green stickers than blue stickers at first
= 3 u - (2 u + 70)
= 3 u - 2 u - 70
= 1 u - 70
= 1 x 80 - 70
= 80 - 70
= 10
(c)
Number of green stickers given away
= 1 u
= 80
Answer(s): (a) 160; (b) 10; (c) 80