Adam has 490 stickers.
After
13 of the blue stickers and
40 green stickers are given away,
there is an equal number of blue and green stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers than green stickers are there at first?
- How many blue stickers are given away?
|
Blue stickers |
Green stickers |
Total |
Before |
3 u |
2 u + 40 |
490 |
Change |
- 1 u |
- 40 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the blue stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 40
= 5 u + 40
5 u + 40 = 490
5 u = 490 - 40
5 u = 450
1 u = 450 ÷ 5 = 90
Number of blue stickers in the end
= 2 u
= 2 x 90
= 180
(b)
Number of more blue stickers than green stickers at first
= 3 u - (2 u + 40)
= 3 u - 2 u - 40
= 1 u - 40
= 1 x 90 - 40
= 90 - 40
= 50
(c)
Number of blue stickers given away
= 1 u
= 90
Answer(s): (a) 180; (b) 50; (c) 90