Adam has 182 stickers.
After
27 of the blue stickers is given away and
another 22 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
7 u |
5 u - 22 |
Change |
- 2 u |
+ 22 |
After |
5 u |
5 u |
(a)
Fraction of the blue stickers left
= 1 -
27 =
57 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 7 u + 5 u - 22
= 12 u - 22
12 u - 22 = 182
12 u = 182 + 22
12 u = 204
1 u = 204 ÷ 12 = 17
Number of blue stickers in the end
= 5 u
= 5 x 17
= 85
(b)
Number of less green stickers than blue stickers at first
= 7 u - (5 u - 22)
= 7 u - 5 u + 22
= 2 u + 22
= 2 x 17 + 22
= 34 + 22
= 56
(c)
Number of blue stickers given away
= 2 u
= 2 x 17
= 34
Answer(s): (a) 85; (b) 56; (c) 34