Adam has 76 stickers.
After
35 of the blue stickers is given away and
another 29 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
5 u |
2 u - 29 |
Change |
- 3 u |
+ 29 |
After |
2 u |
2 u |
(a)
Fraction of the blue stickers left
= 1 -
35 =
25 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 29
= 7 u - 29
7 u - 29 = 76
7 u = 76 + 29
7 u = 105
1 u = 105 ÷ 7 = 15
Number of blue stickers in the end
= 2 u
= 2 x 15
= 30
(b)
Number of less green stickers than blue stickers at first
= 5 u - (2 u - 29)
= 5 u - 2 u + 29
= 3 u + 29
= 3 x 15 + 29
= 45 + 29
= 74
(c)
Number of blue stickers given away
= 3 u
= 3 x 15
= 45
Answer(s): (a) 30; (b) 74; (c) 45