Adam has 191 stickers.
After
58 of the green stickers is given away and
another 7 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
8 u |
3 u - 7 |
Change |
- 5 u |
+ 7 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
58 =
38 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 8 u + 3 u - 7
= 11 u - 7
11 u - 7 = 191
11 u = 191 + 7
11 u = 198
1 u = 198 ÷ 11 = 18
Number of green stickers in the end
= 3 u
= 3 x 18
= 54
(b)
Number of less red stickers than green stickers at first
= 8 u - (3 u - 7)
= 8 u - 3 u + 7
= 5 u + 7
= 5 x 18 + 7
= 90 + 7
= 97
(c)
Number of green stickers given away
= 5 u
= 5 x 18
= 90
Answer(s): (a) 54; (b) 97; (c) 90