Adam has 107 stickers.
After
58 of the blue stickers is given away and
another 25 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
8 u |
3 u - 25 |
Change |
- 5 u |
+ 25 |
After |
3 u |
3 u |
(a)
Fraction of the blue stickers left
= 1 -
58 =
38 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 8 u + 3 u - 25
= 11 u - 25
11 u - 25 = 107
11 u = 107 + 25
11 u = 132
1 u = 132 ÷ 11 = 12
Number of blue stickers in the end
= 3 u
= 3 x 12
= 36
(b)
Number of less green stickers than blue stickers at first
= 8 u - (3 u - 25)
= 8 u - 3 u + 25
= 5 u + 25
= 5 x 12 + 25
= 60 + 25
= 85
(c)
Number of blue stickers given away
= 5 u
= 5 x 12
= 60
Answer(s): (a) 36; (b) 85; (c) 60