Adam has 52 stickers.
After
710 of the blue stickers is given away and
another 13 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
10 u |
3 u - 13 |
Change |
- 7 u |
+ 13 |
After |
3 u |
3 u |
(a)
Fraction of the blue stickers left
= 1 -
710 =
310 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 10 u + 3 u - 13
= 13 u - 13
13 u - 13 = 52
13 u = 52 + 13
13 u = 65
1 u = 65 ÷ 13 = 5
Number of blue stickers in the end
= 3 u
= 3 x 5
= 15
(b)
Number of less green stickers than blue stickers at first
= 10 u - (3 u - 13)
= 10 u - 3 u + 13
= 7 u + 13
= 7 x 5 + 13
= 35 + 13
= 48
(c)
Number of blue stickers given away
= 7 u
= 7 x 5
= 35
Answer(s): (a) 15; (b) 48; (c) 35