Adam has 86 stickers.
After
27 of the red stickers is given away and
another 10 blue stickers are bought,
there is an equal number of red and blue stickers.
- How many red stickers are there in the end?
- How many less blue stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Blue |
Before |
7 u |
5 u - 10 |
Change |
- 2 u |
+ 10 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
27 =
57 The number of red stickers and blue stickers in the end is the same.
Total number of stickers at first
= 7 u + 5 u - 10
= 12 u - 10
12 u - 10 = 86
12 u = 86 + 10
12 u = 96
1 u = 96 ÷ 12 = 8
Number of red stickers in the end
= 5 u
= 5 x 8
= 40
(b)
Number of less blue stickers than red stickers at first
= 7 u - (5 u - 10)
= 7 u - 5 u + 10
= 2 u + 10
= 2 x 8 + 10
= 16 + 10
= 26
(c)
Number of red stickers given away
= 2 u
= 2 x 8
= 16
Answer(s): (a) 40; (b) 26; (c) 16