Adam has 175 stickers.
After
38 of the red stickers is given away and
another 46 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
8 u |
5 u - 46 |
Change |
- 3 u |
+ 46 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
38 =
58 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 8 u + 5 u - 46
= 13 u - 46
13 u - 46 = 175
13 u = 175 + 46
13 u = 221
1 u = 221 ÷ 13 = 17
Number of red stickers in the end
= 5 u
= 5 x 17
= 85
(b)
Number of less green stickers than red stickers at first
= 8 u - (5 u - 46)
= 8 u - 5 u + 46
= 3 u + 46
= 3 x 17 + 46
= 51 + 46
= 97
(c)
Number of red stickers given away
= 3 u
= 3 x 17
= 51
Answer(s): (a) 85; (b) 97; (c) 51