Adam has 62 stickers.
After
25 of the green stickers is given away and
another 34 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
5 u |
3 u - 34 |
Change |
- 2 u |
+ 34 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
25 =
35 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 5 u + 3 u - 34
= 8 u - 34
8 u - 34 = 62
8 u = 62 + 34
8 u = 96
1 u = 96 ÷ 8 = 12
Number of green stickers in the end
= 3 u
= 3 x 12
= 36
(b)
Number of less red stickers than green stickers at first
= 5 u - (3 u - 34)
= 5 u - 3 u + 34
= 2 u + 34
= 2 x 12 + 34
= 24 + 34
= 58
(c)
Number of green stickers given away
= 2 u
= 2 x 12
= 24
Answer(s): (a) 36; (b) 58; (c) 24