Adam has 77 stickers.
After
38 of the blue stickers is given away and
another 27 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
8 u |
5 u - 27 |
Change |
- 3 u |
+ 27 |
After |
5 u |
5 u |
(a)
Fraction of the blue stickers left
= 1 -
38 =
58 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 8 u + 5 u - 27
= 13 u - 27
13 u - 27 = 77
13 u = 77 + 27
13 u = 104
1 u = 104 ÷ 13 = 8
Number of blue stickers in the end
= 5 u
= 5 x 8
= 40
(b)
Number of less green stickers than blue stickers at first
= 8 u - (5 u - 27)
= 8 u - 5 u + 27
= 3 u + 27
= 3 x 8 + 27
= 24 + 27
= 51
(c)
Number of blue stickers given away
= 3 u
= 3 x 8
= 24
Answer(s): (a) 40; (b) 51; (c) 24