Adam has 91 stickers.
After
37 of the blue stickers is given away and
another 41 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
7 u |
4 u - 41 |
Change |
- 3 u |
+ 41 |
After |
4 u |
4 u |
(a)
Fraction of the blue stickers left
= 1 -
37 =
47 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 7 u + 4 u - 41
= 11 u - 41
11 u - 41 = 91
11 u = 91 + 41
11 u = 132
1 u = 132 ÷ 11 = 12
Number of blue stickers in the end
= 4 u
= 4 x 12
= 48
(b)
Number of less green stickers than blue stickers at first
= 7 u - (4 u - 41)
= 7 u - 4 u + 41
= 3 u + 41
= 3 x 12 + 41
= 36 + 41
= 77
(c)
Number of blue stickers given away
= 3 u
= 3 x 12
= 36
Answer(s): (a) 48; (b) 77; (c) 36