Adam has 56 stickers.
After
37 of the blue stickers is given away and
another 10 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
7 u |
4 u - 10 |
Change |
- 3 u |
+ 10 |
After |
4 u |
4 u |
(a)
Fraction of the blue stickers left
= 1 -
37 =
47 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 7 u + 4 u - 10
= 11 u - 10
11 u - 10 = 56
11 u = 56 + 10
11 u = 66
1 u = 66 ÷ 11 = 6
Number of blue stickers in the end
= 4 u
= 4 x 6
= 24
(b)
Number of less green stickers than blue stickers at first
= 7 u - (4 u - 10)
= 7 u - 4 u + 10
= 3 u + 10
= 3 x 6 + 10
= 18 + 10
= 28
(c)
Number of blue stickers given away
= 3 u
= 3 x 6
= 18
Answer(s): (a) 24; (b) 28; (c) 18