Adam has 50 stickers.
After
25 of the green stickers is given away and
another 14 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
5 u |
3 u - 14 |
Change |
- 2 u |
+ 14 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
25 =
35 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 5 u + 3 u - 14
= 8 u - 14
8 u - 14 = 50
8 u = 50 + 14
8 u = 64
1 u = 64 ÷ 8 = 8
Number of green stickers in the end
= 3 u
= 3 x 8
= 24
(b)
Number of less blue stickers than green stickers at first
= 5 u - (3 u - 14)
= 5 u - 3 u + 14
= 2 u + 14
= 2 x 8 + 14
= 16 + 14
= 30
(c)
Number of green stickers given away
= 2 u
= 2 x 8
= 16
Answer(s): (a) 24; (b) 30; (c) 16