Adam has 175 stickers.
After
58 of the green stickers is given away and
another 23 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
8 u |
3 u - 23 |
Change |
- 5 u |
+ 23 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
58 =
38 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 8 u + 3 u - 23
= 11 u - 23
11 u - 23 = 175
11 u = 175 + 23
11 u = 198
1 u = 198 ÷ 11 = 18
Number of green stickers in the end
= 3 u
= 3 x 18
= 54
(b)
Number of less blue stickers than green stickers at first
= 8 u - (3 u - 23)
= 8 u - 3 u + 23
= 5 u + 23
= 5 x 18 + 23
= 90 + 23
= 113
(c)
Number of green stickers given away
= 5 u
= 5 x 18
= 90
Answer(s): (a) 54; (b) 113; (c) 90