Adam has 199 stickers.
After
25 of the blue stickers is given away and
another 41 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
5 u |
3 u - 41 |
Change |
- 2 u |
+ 41 |
After |
3 u |
3 u |
(a)
Fraction of the blue stickers left
= 1 -
25 =
35 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 5 u + 3 u - 41
= 8 u - 41
8 u - 41 = 199
8 u = 199 + 41
8 u = 240
1 u = 240 ÷ 8 = 30
Number of blue stickers in the end
= 3 u
= 3 x 30
= 90
(b)
Number of less green stickers than blue stickers at first
= 5 u - (3 u - 41)
= 5 u - 3 u + 41
= 2 u + 41
= 2 x 30 + 41
= 60 + 41
= 101
(c)
Number of blue stickers given away
= 2 u
= 2 x 30
= 60
Answer(s): (a) 90; (b) 101; (c) 60