Adam has 164 stickers.
After
57 of the blue stickers is given away and
another 43 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
7 u |
2 u - 43 |
Change |
- 5 u |
+ 43 |
After |
2 u |
2 u |
(a)
Fraction of the blue stickers left
= 1 -
57 =
27 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 7 u + 2 u - 43
= 9 u - 43
9 u - 43 = 164
9 u = 164 + 43
9 u = 207
1 u = 207 ÷ 9 = 23
Number of blue stickers in the end
= 2 u
= 2 x 23
= 46
(b)
Number of less green stickers than blue stickers at first
= 7 u - (2 u - 43)
= 7 u - 2 u + 43
= 5 u + 43
= 5 x 23 + 43
= 115 + 43
= 158
(c)
Number of blue stickers given away
= 5 u
= 5 x 23
= 115
Answer(s): (a) 46; (b) 158; (c) 115