Adam has 145 stickers.
After
35 of the green stickers is given away and
another 23 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
5 u |
2 u - 23 |
Change |
- 3 u |
+ 23 |
After |
2 u |
2 u |
(a)
Fraction of the green stickers left
= 1 -
35 =
25 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 23
= 7 u - 23
7 u - 23 = 145
7 u = 145 + 23
7 u = 168
1 u = 168 ÷ 7 = 24
Number of green stickers in the end
= 2 u
= 2 x 24
= 48
(b)
Number of less red stickers than green stickers at first
= 5 u - (2 u - 23)
= 5 u - 2 u + 23
= 3 u + 23
= 3 x 24 + 23
= 72 + 23
= 95
(c)
Number of green stickers given away
= 3 u
= 3 x 24
= 72
Answer(s): (a) 48; (b) 95; (c) 72