Adam has 188 stickers.
After
35 of the green stickers is given away and
another 50 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
5 u |
2 u - 50 |
Change |
- 3 u |
+ 50 |
After |
2 u |
2 u |
(a)
Fraction of the green stickers left
= 1 -
35 =
25 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 50
= 7 u - 50
7 u - 50 = 188
7 u = 188 + 50
7 u = 238
1 u = 238 ÷ 7 = 34
Number of green stickers in the end
= 2 u
= 2 x 34
= 68
(b)
Number of less red stickers than green stickers at first
= 5 u - (2 u - 50)
= 5 u - 2 u + 50
= 3 u + 50
= 3 x 34 + 50
= 102 + 50
= 152
(c)
Number of green stickers given away
= 3 u
= 3 x 34
= 102
Answer(s): (a) 68; (b) 152; (c) 102