Adam has 161 stickers.
After
59 of the blue stickers is given away and
another 34 red stickers are bought,
there is an equal number of blue and red stickers.
- How many blue stickers are there in the end?
- How many less red stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Red |
Before |
9 u |
4 u - 34 |
Change |
- 5 u |
+ 34 |
After |
4 u |
4 u |
(a)
Fraction of the blue stickers left
= 1 -
59 =
49 The number of blue stickers and red stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 34
= 13 u - 34
13 u - 34 = 161
13 u = 161 + 34
13 u = 195
1 u = 195 ÷ 13 = 15
Number of blue stickers in the end
= 4 u
= 4 x 15
= 60
(b)
Number of less red stickers than blue stickers at first
= 9 u - (4 u - 34)
= 9 u - 4 u + 34
= 5 u + 34
= 5 x 15 + 34
= 75 + 34
= 109
(c)
Number of blue stickers given away
= 5 u
= 5 x 15
= 75
Answer(s): (a) 60; (b) 109; (c) 75