Adam has 171 stickers.
After
37 of the green stickers is given away and
another 16 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
7 u |
4 u - 16 |
Change |
- 3 u |
+ 16 |
After |
4 u |
4 u |
(a)
Fraction of the green stickers left
= 1 -
37 =
47 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 7 u + 4 u - 16
= 11 u - 16
11 u - 16 = 171
11 u = 171 + 16
11 u = 187
1 u = 187 ÷ 11 = 17
Number of green stickers in the end
= 4 u
= 4 x 17
= 68
(b)
Number of less red stickers than green stickers at first
= 7 u - (4 u - 16)
= 7 u - 4 u + 16
= 3 u + 16
= 3 x 17 + 16
= 51 + 16
= 67
(c)
Number of green stickers given away
= 3 u
= 3 x 17
= 51
Answer(s): (a) 68; (b) 67; (c) 51