Adam has 196 stickers.
After
49 of the green stickers is given away and
another 28 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
9 u |
5 u - 28 |
Change |
- 4 u |
+ 28 |
After |
5 u |
5 u |
(a)
Fraction of the green stickers left
= 1 -
49 =
59 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 28
= 14 u - 28
14 u - 28 = 196
14 u = 196 + 28
14 u = 224
1 u = 224 ÷ 14 = 16
Number of green stickers in the end
= 5 u
= 5 x 16
= 80
(b)
Number of less red stickers than green stickers at first
= 9 u - (5 u - 28)
= 9 u - 5 u + 28
= 4 u + 28
= 4 x 16 + 28
= 64 + 28
= 92
(c)
Number of green stickers given away
= 4 u
= 4 x 16
= 64
Answer(s): (a) 80; (b) 92; (c) 64