Adam has 100 stickers.
After
59 of the blue stickers is given away and
another 43 red stickers are bought,
there is an equal number of blue and red stickers.
- How many blue stickers are there in the end?
- How many less red stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Red |
Before |
9 u |
4 u - 43 |
Change |
- 5 u |
+ 43 |
After |
4 u |
4 u |
(a)
Fraction of the blue stickers left
= 1 -
59 =
49 The number of blue stickers and red stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 43
= 13 u - 43
13 u - 43 = 100
13 u = 100 + 43
13 u = 143
1 u = 143 ÷ 13 = 11
Number of blue stickers in the end
= 4 u
= 4 x 11
= 44
(b)
Number of less red stickers than blue stickers at first
= 9 u - (4 u - 43)
= 9 u - 4 u + 43
= 5 u + 43
= 5 x 11 + 43
= 55 + 43
= 98
(c)
Number of blue stickers given away
= 5 u
= 5 x 11
= 55
Answer(s): (a) 44; (b) 98; (c) 55