Adam has 190 stickers.
After
37 of the green stickers is given away and
another 8 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
7 u |
4 u - 8 |
Change |
- 3 u |
+ 8 |
After |
4 u |
4 u |
(a)
Fraction of the green stickers left
= 1 -
37 =
47 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 7 u + 4 u - 8
= 11 u - 8
11 u - 8 = 190
11 u = 190 + 8
11 u = 198
1 u = 198 ÷ 11 = 18
Number of green stickers in the end
= 4 u
= 4 x 18
= 72
(b)
Number of less blue stickers than green stickers at first
= 7 u - (4 u - 8)
= 7 u - 4 u + 8
= 3 u + 8
= 3 x 18 + 8
= 54 + 8
= 62
(c)
Number of green stickers given away
= 3 u
= 3 x 18
= 54
Answer(s): (a) 72; (b) 62; (c) 54