Adam has 89 stickers.
After
59 of the green stickers is given away and
another 28 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
9 u |
4 u - 28 |
Change |
- 5 u |
+ 28 |
After |
4 u |
4 u |
(a)
Fraction of the green stickers left
= 1 -
59 =
49 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 28
= 13 u - 28
13 u - 28 = 89
13 u = 89 + 28
13 u = 117
1 u = 117 ÷ 13 = 9
Number of green stickers in the end
= 4 u
= 4 x 9
= 36
(b)
Number of less red stickers than green stickers at first
= 9 u - (4 u - 28)
= 9 u - 4 u + 28
= 5 u + 28
= 5 x 9 + 28
= 45 + 28
= 73
(c)
Number of green stickers given away
= 5 u
= 5 x 9
= 45
Answer(s): (a) 36; (b) 73; (c) 45