Adam has 162 stickers.
After
49 of the red stickers is given away and
another 34 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
9 u |
5 u - 34 |
Change |
- 4 u |
+ 34 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
49 =
59 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 34
= 14 u - 34
14 u - 34 = 162
14 u = 162 + 34
14 u = 196
1 u = 196 ÷ 14 = 14
Number of red stickers in the end
= 5 u
= 5 x 14
= 70
(b)
Number of less green stickers than red stickers at first
= 9 u - (5 u - 34)
= 9 u - 5 u + 34
= 4 u + 34
= 4 x 14 + 34
= 56 + 34
= 90
(c)
Number of red stickers given away
= 4 u
= 4 x 14
= 56
Answer(s): (a) 70; (b) 90; (c) 56