Adam has 166 stickers.
After
710 of the green stickers is given away and
another 29 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
10 u |
3 u - 29 |
Change |
- 7 u |
+ 29 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
710 =
310 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 10 u + 3 u - 29
= 13 u - 29
13 u - 29 = 166
13 u = 166 + 29
13 u = 195
1 u = 195 ÷ 13 = 15
Number of green stickers in the end
= 3 u
= 3 x 15
= 45
(b)
Number of less red stickers than green stickers at first
= 10 u - (3 u - 29)
= 10 u - 3 u + 29
= 7 u + 29
= 7 x 15 + 29
= 105 + 29
= 134
(c)
Number of green stickers given away
= 7 u
= 7 x 15
= 105
Answer(s): (a) 45; (b) 134; (c) 105