Adam has 175 stickers.
After
49 of the red stickers is given away and
another 49 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
9 u |
5 u - 49 |
Change |
- 4 u |
+ 49 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
49 =
59 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 49
= 14 u - 49
14 u - 49 = 175
14 u = 175 + 49
14 u = 224
1 u = 224 ÷ 14 = 16
Number of red stickers in the end
= 5 u
= 5 x 16
= 80
(b)
Number of less green stickers than red stickers at first
= 9 u - (5 u - 49)
= 9 u - 5 u + 49
= 4 u + 49
= 4 x 16 + 49
= 64 + 49
= 113
(c)
Number of red stickers given away
= 4 u
= 4 x 16
= 64
Answer(s): (a) 80; (b) 113; (c) 64