Adam has 187 stickers.
After
57 of the blue stickers is given away and
another 47 red stickers are bought,
there is an equal number of blue and red stickers.
- How many blue stickers are there in the end?
- How many less red stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Red |
Before |
7 u |
2 u - 47 |
Change |
- 5 u |
+ 47 |
After |
2 u |
2 u |
(a)
Fraction of the blue stickers left
= 1 -
57 =
27 The number of blue stickers and red stickers in the end is the same.
Total number of stickers at first
= 7 u + 2 u - 47
= 9 u - 47
9 u - 47 = 187
9 u = 187 + 47
9 u = 234
1 u = 234 ÷ 9 = 26
Number of blue stickers in the end
= 2 u
= 2 x 26
= 52
(b)
Number of less red stickers than blue stickers at first
= 7 u - (2 u - 47)
= 7 u - 2 u + 47
= 5 u + 47
= 5 x 26 + 47
= 130 + 47
= 177
(c)
Number of blue stickers given away
= 5 u
= 5 x 26
= 130
Answer(s): (a) 52; (b) 177; (c) 130