Adam has 188 stickers.
After
310 of the green stickers is given away and
another 50 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
10 u |
7 u - 50 |
Change |
- 3 u |
+ 50 |
After |
7 u |
7 u |
(a)
Fraction of the green stickers left
= 1 -
310 =
710 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 10 u + 7 u - 50
= 17 u - 50
17 u - 50 = 188
17 u = 188 + 50
17 u = 238
1 u = 238 ÷ 17 = 14
Number of green stickers in the end
= 7 u
= 7 x 14
= 98
(b)
Number of less blue stickers than green stickers at first
= 10 u - (7 u - 50)
= 10 u - 7 u + 50
= 3 u + 50
= 3 x 14 + 50
= 42 + 50
= 92
(c)
Number of green stickers given away
= 3 u
= 3 x 14
= 42
Answer(s): (a) 98; (b) 92; (c) 42