Adam has 85 stickers.
After
29 of the green stickers is given away and
another 27 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
9 u |
7 u - 27 |
Change |
- 2 u |
+ 27 |
After |
7 u |
7 u |
(a)
Fraction of the green stickers left
= 1 -
29 =
79 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 9 u + 7 u - 27
= 16 u - 27
16 u - 27 = 85
16 u = 85 + 27
16 u = 112
1 u = 112 ÷ 16 = 7
Number of green stickers in the end
= 7 u
= 7 x 7
= 49
(b)
Number of less blue stickers than green stickers at first
= 9 u - (7 u - 27)
= 9 u - 7 u + 27
= 2 u + 27
= 2 x 7 + 27
= 14 + 27
= 41
(c)
Number of green stickers given away
= 2 u
= 2 x 7
= 14
Answer(s): (a) 49; (b) 41; (c) 14