Adam has 149 stickers.
After
49 of the green stickers is given away and
another 33 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
9 u |
5 u - 33 |
Change |
- 4 u |
+ 33 |
After |
5 u |
5 u |
(a)
Fraction of the green stickers left
= 1 -
49 =
59 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 33
= 14 u - 33
14 u - 33 = 149
14 u = 149 + 33
14 u = 182
1 u = 182 ÷ 14 = 13
Number of green stickers in the end
= 5 u
= 5 x 13
= 65
(b)
Number of less blue stickers than green stickers at first
= 9 u - (5 u - 33)
= 9 u - 5 u + 33
= 4 u + 33
= 4 x 13 + 33
= 52 + 33
= 85
(c)
Number of green stickers given away
= 4 u
= 4 x 13
= 52
Answer(s): (a) 65; (b) 85; (c) 52