Adam has 146 stickers.
After
47 of the green stickers is given away and
another 44 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
7 u |
3 u - 44 |
Change |
- 4 u |
+ 44 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
47 =
37 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 7 u + 3 u - 44
= 10 u - 44
10 u - 44 = 146
10 u = 146 + 44
10 u = 190
1 u = 190 ÷ 10 = 19
Number of green stickers in the end
= 3 u
= 3 x 19
= 57
(b)
Number of less blue stickers than green stickers at first
= 7 u - (3 u - 44)
= 7 u - 3 u + 44
= 4 u + 44
= 4 x 19 + 44
= 76 + 44
= 120
(c)
Number of green stickers given away
= 4 u
= 4 x 19
= 76
Answer(s): (a) 57; (b) 120; (c) 76