Adam has 112 stickers.
After ²₅ of the green stickers is given away and
another 40 red stickers are bought,
there is an equal number of green and red stickers.

1. How many green stickers are there in the end?
2. How many less red stickers than green stickers are there at first?
3. How many green stickers are given away?

	Green	Red
Before	5 u	3 u - 40
Change	- 2 u	+ 40
After	3 u	3 u

(a)
Fraction of the green stickers left
= 1 - ²₅
= ³₅

The number of green stickers and red stickers in the end is the same.

Total number of stickers at first
= 5 u + 3 u - 40
= 8 u - 40

8 u - 40 = 112
8 u = 112 + 40
8 u = 152

1 u = 152 ÷ 8 = 19

Number of green stickers in the end
= 3 u
= 3 x 19
= 57

(b)
Number of less red stickers than green stickers at first
= 5 u - (3 u - 40)
= 5 u - 3 u + 40
= 2 u + 40
= 2 x 19 + 40
= 38 + 40
= 78

(c)
Number of green stickers given away
= 2 u
= 2 x 19
= 38

Answer(s): (a) 57; (b) 78; (c) 38