Adam has 197 stickers.
After ⁷₉ of the blue stickers is given away and
another 12 green stickers are bought,
there is an equal number of blue and green stickers.

1. How many blue stickers are there in the end?
2. How many less green stickers than blue stickers are there at first?
3. How many blue stickers are given away?

	Blue	Green
Before	9 u	2 u - 12
Change	- 7 u	+ 12
After	2 u	2 u

(a)
Fraction of the blue stickers left
= 1 - ⁷₉
= ²₉

The number of blue stickers and green stickers in the end is the same.

Total number of stickers at first
= 9 u + 2 u - 12
= 11 u - 12

11 u - 12 = 197
11 u = 197 + 12
11 u = 209

1 u = 209 ÷ 11 = 19

Number of blue stickers in the end
= 2 u
= 2 x 19
= 38

(b)
Number of less green stickers than blue stickers at first
= 9 u - (2 u - 12)
= 9 u - 2 u + 12
= 7 u + 12
= 7 x 19 + 12
= 133 + 12
= 145

(c)
Number of blue stickers given away
= 7 u
= 7 x 19
= 133

Answer(s): (a) 38; (b) 145; (c) 133